Gujarati
Hindi
14.Waves and Sound
easy

A transverse harmonic wave on a string is described by $y = 3 \sin \,(36t + 0.018x + \frac{\pi}{4})$ where $x$ and $y$ are in $cm$ and $t$ in $s$. The least distance between  two sucessive crests in the wave is .... $m$

A

$2.5$

B

$3.5$

C

$1.5$

D

$4.5$

Solution

$\mathrm{k}=.018$

$\lambda=2 \pi / \mathrm{k}=\frac{2 \pi}{.018}=348.88=3.5 \mathrm{\,m}$

Standard 11
Physics

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